Two characters might have identical Unicode skeletons but render differently in specific fonts, or have different skeletons but render identically in a particular typeface. Detecting this requires rendering glyphs and comparing pixel output. No purely Unicode-data-based approach handles it, and UTS #39 does not attempt to.
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arr[j + 1] = key; // 插入到正确位置
deflate.push(chunk, false);，推荐阅读搜狗输入法2026获取更多信息
黄仁勋：今年游戏显卡或会迎来供应紧张
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